Hi,
Disclaimers:
1. There are bound to be discrepancies in the key. I'm just providing a starting point to initiate the process of discussions and debates so that we can ultimately arrive at the legitimate solution.
2. I have left few questions unanswered( which ofcourse I don't know) by simply putting * in place of answer.
3. The answers for which I wasn't sure about carry ** before question number.
SET C Answers:
Answer SetC
1.A-----flux density in emw
2.C---antiferro
3.A—reading of Galvanomtr
4.C---slope=planks const
5.*--compton
6.C--j=1/2
7.A---energy=5mc^2/3
8.B---U235
9.A—form of wave function
10.B---carnot relation betwn y and x
11.*---2nd order transition
12.B---harmonic osccil min energy etc
13.B--- newton ring in a liq
**14.D--- diff function of numbr of lines
15.A---coin’ll appear shiny
16.C---SHM ellipse
**17. C----distnce betwn 2 dark
18.C--- 1.44
19.D—centre of mass v=0
20.C—emitter is fwd biased…
21.A…zero electric field at centre
22.D….BI along y
23.D….currnt in j direction
24.A….5ohm
25.C…problity current
26.A…1/a27.C….leptons forces
28.B..plank
29.D….kinetic energy equalfor both H and N
30.A…escape vel non of above
31.* projection of circular motion
32.D…work done by chain
33.D….zero earth sun
34.D…escape vel 4R
35.B…m=13
**36.C…will be virtual
37.B…population inversion in Ne
38.C…both mirage n plane mirror image
**39.B…van de graff
40.A….cyclotron
41.D…q/2 q/2
**42.B….B=mu*H di ferro para
43.C….particle at rest decay
44.C….flywheel
45.A…..range max height
46.A….phase diff b/w SHM
47.C….speed of masses in G
48.B…exponentially decresing
49.A….kinetic energy of planet
**50D….both E and P conserved
51.B…new terminal vel
52.D…observer ‘ll hear 1 beat
53.C….MI of disc
54.D = 0.65
55.A…122.4ev
56.D…transmission prob
**57.B…stern gerlach
**58.B…Zeeman
59.A…p-q/pq
60.*
61.C….0.79ev
62.C…e-2
63.B…wave function continuos
64.A…X ray l alpha k alpha
65.B…gamma mixture=1.5
66.C…entropy increase
67.D….heat capacity
68.D..weins displcmnt law
69.B….1.5J
70.C…drift n diffusion
71.D…acquire negtve chrge
72.C…exponential way
73.B…thin film appears black
74.B…velocity vector
75.A…R-1 escape vel
76.C….square root of temp
77.B….20ma
78.D….independnt of r
**79.A…dopant concentration
80.B…r1v1/r2
81.D…speed=1
82.D…hysteresis
83.C…Huygens eyepiece
84.D….interfrnce beam coherent etc.
85.A…50000
86.D…60 cm
87.B…30degree
88.A…=1time period ratio alpha and proton
89.B….-3E/5
90.A…2/3V
91.C…L>2f
**92.D HE-Ne grating---will remain same
**93.C microscope telescope
**94.A…0.6mm(ooptions were in nm)
95.A…parabolic mirror
96.C…harmonic oscill resonance
97.C…moving clock
98.B….capillary h to h/3
99.D…Be++
100.D…electricflux zero
101.A….YDSE Stmt 1 2 type(101-105)
**102.C
103.C….particle barrie
**104.C…streamline
105.D…relativity
106.A…soft iron
107.A…van der wall work
108.D….chnge in entropy
**109.B…D and eta unchanged
110.A….logic gates
111.B…zener 250ohm
112.D….p/n impurity band gap unchnged
113.* opacity
**114.B…astigmatism
115.B….ratio of intensity 1/3
116.D….plane polarized light 1,2,3
117.A…=vel of light
118.B….Q factor
119.B…45 degree phase diff
120.D….By Bx Bz
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34 comments:
hey aman, mine set was D, I wanna confirm answer to the problem which said a particle of Mass M disintegrates into two of mass m, velocity was reqd.
i calculated it as (1-4m^2/M^2)^1/2, i think.... any input frm u ??
yes u r correct...i have updated the key
your problem 13.. they are talking about the "area" of circular ring.. there wont be a square root I guess..
14 is A for sure.. http://www.diasindia.com/solution.htm
and 15th will be B..
--- my perceptions.
your 17th is correct..
but for 30th.. why is the ans not mv^2/3R simply.. because.. v = sqrt(3RT/m)
I DIFFER FROM UR ANSWERS ON THE FOLLOWING QUESTIONS...PLS CHECK..WE CAN EVEN HV A DISCUSSION ..
5 A
6 C
14 D
17 C
27 D
30 A
31 B
32 A
42 B
45 A
52 C
54 D
64 A
75 A
88 A
97 C
107 A
109 C
113 A
I DIFFER FROM UR ANSWERS ON THE FOLLOWING QUESTIONS...PLS CHECK..WE CAN EVEN HV A DISCUSSION ..
5 A
6 C
14 D
17 C
27 D
30 A
31 B
32 A
42 B
45 A
52 C
54 D
64 A
75 A
88 A
97 C
107 A
109 C
113 A
45 ka A hoga boss! angle will be 60 degree so
u^2 * sin (120)/g
89 ka bhi shayad A hona chahiye.. because the position of the point where we need the elec field are being interchanged.. so an additional minus sign.
boss 90 ka shayad 2/3 V hona chahiye. the two sides of the circuit can be treated as independednt as long as there is no internal resistance in the battery.. so (2/15)*5V
@pankaj
dias key given is for 2009 paper dont refer it
13 B ( u r correct)
15 A (i dont know soln but seen somewhere the answer i think the same question was asked few yrs back)
89 B (the direction of both fields should be oppostite so a - sign)
90 C (i don't think internal resistnce to be conssidered)
@blogmaster
5&6 no idea
14D (if u increase the numbr of lines u r basically imroving the resolution and more the resolution sharper the diff curve)
27C (leptons never interact with strong forces)
30A ( shud simply be A)
31B (though i havnt done but i think looking from diameter of a circle motion'll appear as a SHM)
32D (net acceleration g'=g-g/4)
42D (i never learnt abt any exception...but i m not sure either)
45A
52D(intnsity ratio of 2 sounds is just the square of their amplitude ratio isnt it?)
54B( by definition of half life)
64A (u r correct)
75A (a silly mistake!)
88C (T=2pim/qb) just calculated it give ur soln
107A (u r corrct)
109B these are inherentproperties of a gas how it can be changed by changing volume
113 no idea boss
...share ur opinions and thoughts!
52
max amplitude will be 10 and min amplitude will be 2 ..thrfore intensity ratio 100/4 = 25/1 and not 9/4
88
T = 2 pi m / qB rite
but mass of alpha is 4 times tht of proton and charge is 2 times tht of proton
so 4/2 = 2 times the period of proton
109
fr an ideal gas at constant pressure if u increase volume by 4 times then temp also increases 4 times fr the same number of molecules..
now visc coeff proportional to sqroot of T
and diff coeff proportional to T to the power 3/2
54
proportion left = exp(-lembda x t)
for t = half life / 2
proportion left = exp(- 0.693/2)
= 1- 0.693/2
= 0.65
so answer is D
42
the question is saying that MU is constant over a wide range of H ..essentially implying a linear magnetic media ...which are diamagnets and paramagnets only
hence answer is B
90
the answer will be 2/3 V hence the answer is A
6
in the excited states
for n=2 l=0 2 states with j=1/2
for n=2 l=1 we get j=3/2 and 1/2 using l and s values
therefore again 2 j=1/2 states are available
total is 4
answer is C
97
moving clocks always measure less time as they run slow..
in F frame time is measured as 2x/c
value of gamma is 2/root3
therefore time showed by clock which is in F' frame will be :
time in Fframe /gamma = root3 x/c
hence answer is D
i think for 54 n 88 u r correct
109 still not convinced that coeff of viscosity can be varied by chnging volume....coeff also depends on density...so chnging volume wont affect it?
97 t'= (t-vx/c^2)*gamma gives C
42 ok i didnt know abt that
97
ur equation is rite
just put in the values
t = 2x/c
v = c/2
and gamma = 2/root3
u will get answer as D
wat is opinion abt 6 , 52 and 90 ??
coeff of viscosity = 1/3 * density * mean free path *average speed
density = p / RT
p is constant
mean free path = 1/(root2 pi d^2 n)
which makes it proportional to T and inversely proportional to p ..but p is constant
average speed is proportional to rootT
so on the whole viscosity coeff is directly proportional to root T
fr diffusion coeff=1/3*path*speed
so diffusion coeff on the whole is proportional to T^(3/2)
good discussion guys...i wish i had my paper with me...
I used to perceive I had good speed in physics....but i could not even read all problems...some of them were so easy...is it that i was too slow or it happens with others as well...
@mayank
physics paper is always lengthy...
i have always attempted not more than 99-100 questions...
everytime not able to read 5-10 questions....
6 and 90 i have already chnged d answers....
6C and 90 A
52 i still believe 9/4 is the required ratio of two sounds...we r dealing with beats not d interference
whatz ur take on 93 102 104 103
neway wat r ur scores?
for 93 i think answer is D
101 to 105 questions ...i wasn't able to attempt
beats ultimately involve interference ...refer to its derivation..
i hope u found my new explanations fr 97 and 109 convincing..
my score wud remain between 80 and 85 in physics
u r frm which batch of iitg?
ya ur solutn look convincing...
..i m frm 2009 batch of iitg...my 2nd attmpt i wrote mains last year
wat abt u...which attmpt?
@aman: howz abt u're last year's impression of physics paper. I think of getting credit of just 72 in physics and 68 in GS...can i derive motivation for mains ?? just a small hope can motivate me enough... :)
m frm IIIT Jabalpur n joined Customs as Inspector just to channelize myself into civilservices...
@dhakad banna
myself frm iitk 2006 batch
4th attempt
@mayank
pre scores just dont matter...n ur score is decent infact very good...last yr kumar prashant too scored same in ur range n qualified with AIR 26...when it comes to mains its all diff ball game
@blogmaster
watz ur 2nd subjct....n r u in job or preparing wholesomely?
nyway visio ias key is out but i dont have set A paper
hi guys ,
wanna give some clarification of some questions
que 89.
ans a
explaination.
as the two charges are opposite in nature so direction of EF at different points will remain same.
qus 30.
ans a
there is no need to go into the nitty gritty of the concept,jus apply simple formula and ans is urs.
qus 58.
ans c
exp. as inthe first statement he has not taken anmls. zeeman effect so in normal one always split into three levels which are equally spaced.
qus 70
ans b
though flow of current is both due to diffusion and drift current but in qus hey have used the word "mainly".so main current is due to diffusion in forward bias.
qus 77
ans d
exp. as the polarity of diode voltage is same as tat of applied voltage no current can flow through the diode until n unless applied voltage is greater then diode voltage.
qus 101
ans a
qus 102
ans b
exp. resistivity of a semicond decreases as the no. of current carriers increares exponentially with temp.and in cond rate of collision increases with temp and hence resistivity increases.so reasons of resistivity change are different in two cases.
qus 104
ans a
exp very obvious bernls theorem
qus 105
ans c
statement 2 is wrong as the velocity will lie in x-y plane .
qus 109
ans b
i welcome if there is any query frrom ur side..........
Thanks aman !
I refuse to agree on Question 6(set C). Answer should be 2.
n=2 So possible values of l= 1,0
Therefore values of j=3/2,1/2 for(l=1) and j=1/2 and -1/2 for(l=0)
So answer is A) 2
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